Base | Representation |
---|---|
bin | 11001101101000001100110… |
… | …111100011101101111010111 |
3 | 112211021000120222110021000121 |
4 | 121231001212330131233113 |
5 | 104304113201141412312 |
6 | 1040232140050252411 |
7 | 32545152040461562 |
oct | 3155014674355727 |
9 | 484230528407017 |
10 | 113045266357207 |
11 | 33024256858038 |
12 | 10818b1ab87107 |
13 | 4b10179c611c2 |
14 | 1dcb5c49dd4d9 |
15 | d10877e5a707 |
hex | 66d066f1dbd7 |
113045266357207 has 2 divisors, whose sum is σ = 113045266357208. Its totient is φ = 113045266357206.
The previous prime is 113045266357201. The next prime is 113045266357249. The reversal of 113045266357207 is 702753662540311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113045266357207 - 227 = 113045132139479 is a prime.
It is a super-3 number, since 3×1130452663572073 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113045266357201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56522633178603 + 56522633178604.
It is an arithmetic number, because the mean of its divisors is an integer number (56522633178604).
Almost surely, 2113045266357207 is an apocalyptic number.
113045266357207 is a deficient number, since it is larger than the sum of its proper divisors (1).
113045266357207 is an equidigital number, since it uses as much as digits as its factorization.
113045266357207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6350400, while the sum is 52.
The spelling of 113045266357207 in words is "one hundred thirteen trillion, forty-five billion, two hundred sixty-six million, three hundred fifty-seven thousand, two hundred seven".
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