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113052531121 is a prime number
BaseRepresentation
bin110100101001001110…
…1001011100110110001
3101210210211021121212021
41221102131023212301
53323012421443441
6123534032031441
711111355442045
oct1512235134661
9353724247767
10113052531121
1143a4422aa02
1219ab1092581
13a878a4493a
145686782025
152e1a0b63d1
hex1a5274b9b1

113052531121 has 2 divisors, whose sum is σ = 113052531122. Its totient is φ = 113052531120.

The previous prime is 113052531103. The next prime is 113052531131. The reversal of 113052531121 is 121135250311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111882891121 + 1169640000 = 334489^2 + 34200^2 .

It is an emirp because it is prime and its reverse (121135250311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113052531121 - 27 = 113052530993 is a prime.

It is a super-4 number, since 4×1130525311214 (a number of 45 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (113052531131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56526265560 + 56526265561.

It is an arithmetic number, because the mean of its divisors is an integer number (56526265561).

Almost surely, 2113052531121 is an apocalyptic number.

It is an amenable number.

113052531121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113052531121 is an equidigital number, since it uses as much as digits as its factorization.

113052531121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 113052531121 its reverse (121135250311), we get a palindrome (234187781432).

The spelling of 113052531121 in words is "one hundred thirteen billion, fifty-two million, five hundred thirty-one thousand, one hundred twenty-one".