113055497 has 2 divisors, whose sum is σ = 113055498. Its totient is φ = 113055496.

The previous prime is 113055487. The next prime is 113055499. The reversal of 113055497 is 794550311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102191881 + 10863616 = 10109^2 + 3296^2 .

It is an emirp because it is prime and its reverse (794550311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113055497 - 2¹² = 113051401 is a prime.

Together with 113055499, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p_6468047 and since 113055497 and 6468047 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (113055499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56527748 + 56527749.

It is an arithmetic number, because the mean of its divisors is an integer number (56527749).

Almost surely, 2^113055497 is an apocalyptic number.

It is an amenable number.

113055497 is a deficient number, since it is larger than the sum of its proper divisors (1).

113055497 is an equidigital number, since it uses as much as digits as its factorization.

113055497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18900, while the sum is 35.

The square root of 113055497 is about 10632.7558516125. The cubic root of 113055497 is about 483.5379458161.

The spelling of 113055497 in words is "one hundred thirteen million, fifty-five thousand, four hundred ninety-seven".