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113093892527617 is a prime number
BaseRepresentation
bin11001101101101110111001…
…010010100101011000000001
3112211102200002211011122202001
4121231232321102211120001
5104310412242441340432
61040310341134024001
732551523041220341
oct3155567122453001
9484380084148661
10113093892527617
1133042939a86631
121082642b948001
134b149291b62c1
141dcdab8ab0d21
15d11c71dc99e7
hex66dbb94a5601

113093892527617 has 2 divisors, whose sum is σ = 113093892527618. Its totient is φ = 113093892527616.

The previous prime is 113093892527549. The next prime is 113093892527689. The reversal of 113093892527617 is 716725298390311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99938589431041 + 13155303096576 = 9996929^2 + 3627024^2 .

It is a cyclic number.

It is not a de Polignac number, because 113093892527617 - 219 = 113093892003329 is a prime.

It is not a weakly prime, because it can be changed into another prime (113093892327617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56546946263808 + 56546946263809.

It is an arithmetic number, because the mean of its divisors is an integer number (56546946263809).

Almost surely, 2113093892527617 is an apocalyptic number.

It is an amenable number.

113093892527617 is a deficient number, since it is larger than the sum of its proper divisors (1).

113093892527617 is an equidigital number, since it uses as much as digits as its factorization.

113093892527617 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34292160, while the sum is 64.

The spelling of 113093892527617 in words is "one hundred thirteen trillion, ninety-three billion, eight hundred ninety-two million, five hundred twenty-seven thousand, six hundred seventeen".