1131000943 has 2 divisors, whose sum is σ = 1131000944. Its totient is φ = 1131000942.

The previous prime is 1131000889. The next prime is 1131000971. The reversal of 1131000943 is 3490001311.

It is a strong prime.

It is an emirp because it is prime and its reverse (3490001311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131000943 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131000043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565500471 + 565500472.

It is an arithmetic number, because the mean of its divisors is an integer number (565500472).

Almost surely, 2^1131000943 is an apocalyptic number.

1131000943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131000943 is an equidigital number, since it uses as much as digits as its factorization.

1131000943 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

The square root of 1131000943 is about 33630.3574616744. The cubic root of 1131000943 is about 1041.8878871498.

The spelling of 1131000943 in words is "one billion, one hundred thirty-one million, nine hundred forty-three", and thus it is an aban number.