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113100112103 = 1131277313841
BaseRepresentation
bin110100101010101001…
…0101100000011100111
3101210221010210222200212
41221111102230003213
53323112112041403
6123542451530035
711112504043106
oct1512522540347
9353833728625
10113100112103
1143a69079230
1219b04bb991b
13a885863c74
14568cc0a03d
152e1e3644d8
hex1a554ac0e7

113100112103 has 24 divisors (see below), whose sum is σ = 127664544528. Its totient is φ = 99365664000.

The previous prime is 113100112093. The next prime is 113100112109. The reversal of 113100112103 is 301211001311.

It is a happy number.

It is not a de Polignac number, because 113100112103 - 28 = 113100111847 is a prime.

It is a super-2 number, since 2×1131001121032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113100112109) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8164463 + ... + 8178303.

It is an arithmetic number, because the mean of its divisors is an integer number (5319356022).

Almost surely, 2113100112103 is an apocalyptic number.

113100112103 is a deficient number, since it is larger than the sum of its proper divisors (14564432425).

113100112103 is a wasteful number, since it uses less digits than its factorization.

113100112103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14687 (or 14656 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 113100112103 its reverse (301211001311), we get a palindrome (414311113414).

The spelling of 113100112103 in words is "one hundred thirteen billion, one hundred million, one hundred twelve thousand, one hundred three".

Divisors: 1 11 31 341 773 961 8503 10571 13841 23963 152251 263593 429071 742853 4719781 8171383 10699093 13301201 117690023 146313211 331671883 3648390713 10281828373 113100112103