Base | Representation |
---|---|
bin | 10000011101010100111… |
… | …011001011110101111111 |
3 | 11000010022102021220022022 |
4 | 100131110323023311333 |
5 | 122012242301344444 |
6 | 2223324052510355 |
7 | 144466156402556 |
oct | 20352473136577 |
9 | 4003272256268 |
10 | 1131001199999 |
11 | 3a6722768440 |
12 | 16324201b3bb |
13 | 8286470a7b8 |
14 | 3ca52892d9d |
15 | 1e6474469ee |
hex | 10754ecbd7f |
1131001199999 has 16 divisors (see below), whose sum is σ = 1259826299424. Its totient is φ = 1006594742400.
The previous prime is 1131001199969. The next prime is 1131001200041. The reversal of 1131001199999 is 9999911001311.
It is a cyclic number.
It is not a de Polignac number, because 1131001199999 - 216 = 1131001134463 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (53).
It is a self number, because there is not a number n which added to its sum of digits gives 1131001199999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131001199929) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1835324 + ... + 2372849.
It is an arithmetic number, because the mean of its divisors is an integer number (78739143714).
Almost surely, 21131001199999 is an apocalyptic number.
1131001199999 is a deficient number, since it is larger than the sum of its proper divisors (128825099425).
1131001199999 is a wasteful number, since it uses less digits than its factorization.
1131001199999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4208698.
The product of its (nonzero) digits is 177147, while the sum is 53.
It can be divided in two parts, 1131001 and 199999, that added together give a cube (1331000 = 1103).
The spelling of 1131001199999 in words is "one trillion, one hundred thirty-one billion, one million, one hundred ninety-nine thousand, nine hundred ninety-nine".
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