Base | Representation |
---|---|
bin | 10101000100010000… |
… | …10001011101111011 |
3 | 1002012012210011010211 |
4 | 22202020101131323 |
5 | 141130330343113 |
6 | 5110140451551 |
7 | 550162342513 |
oct | 124210213573 |
9 | 32165704124 |
10 | 11310012283 |
11 | 4884230699 |
12 | 2237849bb7 |
13 | 10b321c77b |
14 | 79412c843 |
15 | 462dc9b3d |
hex | 2a221177b |
11310012283 has 2 divisors, whose sum is σ = 11310012284. Its totient is φ = 11310012282.
The previous prime is 11310012277. The next prime is 11310012299. The reversal of 11310012283 is 38221001311.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (38221001311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11310012283 is a prime.
It is a super-2 number, since 2×113100122832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11310012683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655006141 + 5655006142.
It is an arithmetic number, because the mean of its divisors is an integer number (5655006142).
Almost surely, 211310012283 is an apocalyptic number.
11310012283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310012283 is an equidigital number, since it uses as much as digits as its factorization.
11310012283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 11310012283 its reverse (38221001311), we get a palindrome (49531013594).
The spelling of 11310012283 in words is "eleven billion, three hundred ten million, twelve thousand, two hundred eighty-three".
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