Base | Representation |
---|---|
bin | 110100101010101001… |
… | …1000001100000111111 |
3 | 101210221010222110021021 |
4 | 1221111103001200333 |
5 | 3323112122344444 |
6 | 123542453445011 |
7 | 11112504560263 |
oct | 1512523014077 |
9 | 353833873237 |
10 | 113100199999 |
11 | 43a69129276 |
12 | 19b05040767 |
13 | a885894c87 |
14 | 568cc300a3 |
15 | 2e1e380584 |
hex | 1a554c183f |
113100199999 has 2 divisors, whose sum is σ = 113100200000. Its totient is φ = 113100199998.
The previous prime is 113100199991. The next prime is 113100200053. The reversal of 113100199999 is 999991001311.
It is a weak prime.
It is an emirp because it is prime and its reverse (999991001311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113100199999 - 23 = 113100199991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113100199991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550099999 + 56550100000.
It is an arithmetic number, because the mean of its divisors is an integer number (56550100000).
Almost surely, 2113100199999 is an apocalyptic number.
113100199999 is a deficient number, since it is larger than the sum of its proper divisors (1).
113100199999 is an equidigital number, since it uses as much as digits as its factorization.
113100199999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 177147, while the sum is 52.
The spelling of 113100199999 in words is "one hundred thirteen billion, one hundred million, one hundred ninety-nine thousand, nine hundred ninety-nine".
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