Base | Representation |
---|---|
bin | 1010010010010101001000… |
… | …1110100000001111011111 |
3 | 1111001020011022211102210112 |
4 | 2210211102032200033133 |
5 | 2440300414234033114 |
6 | 40015431052400235 |
7 | 2245060022254133 |
oct | 244452216401737 |
9 | 44036138742715 |
10 | 11310028424159 |
11 | 3670613214763 |
12 | 1327b6177607b |
13 | 6406b9ab2a4a |
14 | 2b15a05193c3 |
15 | 1492ee48d13e |
hex | a49523a03df |
11310028424159 has 2 divisors, whose sum is σ = 11310028424160. Its totient is φ = 11310028424158.
The previous prime is 11310028424131. The next prime is 11310028424173. The reversal of 11310028424159 is 95142482001311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11310028424159 - 220 = 11310027375583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310028424129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655014212079 + 5655014212080.
It is an arithmetic number, because the mean of its divisors is an integer number (5655014212080).
Almost surely, 211310028424159 is an apocalyptic number.
11310028424159 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310028424159 is an equidigital number, since it uses as much as digits as its factorization.
11310028424159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 41.
The spelling of 11310028424159 in words is "eleven trillion, three hundred ten billion, twenty-eight million, four hundred twenty-four thousand, one hundred fifty-nine".
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