Base | Representation |
---|---|
bin | 11001101101110100110111… |
… | …011001011100000100000111 |
3 | 112211110021122121000121211021 |
4 | 121231310313121130010013 |
5 | 104311013410111032444 |
6 | 1040313321221252011 |
7 | 32552140643215453 |
oct | 3155646731340407 |
9 | 484407577017737 |
10 | 113100303220999 |
11 | 33045629716436 |
12 | 1082771a864007 |
13 | 4b1540b3989b3 |
14 | 1dd0126269663 |
15 | d11ee9ad9584 |
hex | 66dd3765c107 |
113100303220999 has 2 divisors, whose sum is σ = 113100303221000. Its totient is φ = 113100303220998.
The previous prime is 113100303220909. The next prime is 113100303221023. The reversal of 113100303220999 is 999022303001311.
It is a strong prime.
It is an emirp because it is prime and its reverse (999022303001311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113100303220999 - 215 = 113100303188231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113100303220909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550151610499 + 56550151610500.
It is an arithmetic number, because the mean of its divisors is an integer number (56550151610500).
Almost surely, 2113100303220999 is an apocalyptic number.
113100303220999 is a deficient number, since it is larger than the sum of its proper divisors (1).
113100303220999 is an equidigital number, since it uses as much as digits as its factorization.
113100303220999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 78732, while the sum is 43.
The spelling of 113100303220999 in words is "one hundred thirteen trillion, one hundred billion, three hundred three million, two hundred twenty thousand, nine hundred ninety-nine".
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