113100494401 has 2 divisors, whose sum is σ = 113100494402. Its totient is φ = 113100494400.

The previous prime is 113100494371. The next prime is 113100494411. The reversal of 113100494401 is 104494001311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105833102400 + 7267392001 = 325320^2 + 85249^2 .

It is a cyclic number.

It is not a de Polignac number, because 113100494401 - 2¹⁷ = 113100363329 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113100494401.

It is not a weakly prime, because it can be changed into another prime (113100494411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550247200 + 56550247201.

It is an arithmetic number, because the mean of its divisors is an integer number (56550247201).

Almost surely, 2^113100494401 is an apocalyptic number.

It is an amenable number.

113100494401 is a deficient number, since it is larger than the sum of its proper divisors (1).

113100494401 is an equidigital number, since it uses as much as digits as its factorization.

113100494401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 113100494401 its reverse (104494001311), we get a palindrome (217594495712).

The spelling of 113100494401 in words is "one hundred thirteen billion, one hundred million, four hundred ninety-four thousand, four hundred one".