113100494411 has 2 divisors, whose sum is σ = 113100494412. Its totient is φ = 113100494410.

The previous prime is 113100494401. The next prime is 113100494413. The reversal of 113100494411 is 114494001311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113100494411 - 2⁶ = 113100494347 is a prime.

Together with 113100494413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113100494413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550247205 + 56550247206.

It is an arithmetic number, because the mean of its divisors is an integer number (56550247206).

Almost surely, 2^113100494411 is an apocalyptic number.

113100494411 is a deficient number, since it is larger than the sum of its proper divisors (1).

113100494411 is an equidigital number, since it uses as much as digits as its factorization.

113100494411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 29.

Adding to 113100494411 its reverse (114494001311), we get a palindrome (227594495722).

The spelling of 113100494411 in words is "one hundred thirteen billion, one hundred million, four hundred ninety-four thousand, four hundred eleven".