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11310054104341 is a prime number
BaseRepresentation
bin1010010010010101001111…
…0000011101110100010101
31111001020020010011010101101
42210211103300131310111
52440300442322314331
640015433411030101
72245060453451356
oct244452360356425
944036203133341
1011310054104341
113670626764653
121327b6a29b331
136406c2204715
142b15a3ac1d2d
15149301862061
hexa4953c1dd15

11310054104341 has 2 divisors, whose sum is σ = 11310054104342. Its totient is φ = 11310054104340.

The previous prime is 11310054104309. The next prime is 11310054104347. The reversal of 11310054104341 is 14340145001311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9942859432900 + 1367194671441 = 3153230^2 + 1169271^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310054104341 - 25 = 11310054104309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310054104347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655027052170 + 5655027052171.

It is an arithmetic number, because the mean of its divisors is an integer number (5655027052171).

Almost surely, 211310054104341 is an apocalyptic number.

It is an amenable number.

11310054104341 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310054104341 is an equidigital number, since it uses as much as digits as its factorization.

11310054104341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 11310054104341 its reverse (14340145001311), we get a palindrome (25650199105652).

The spelling of 11310054104341 in words is "eleven trillion, three hundred ten billion, fifty-four million, one hundred four thousand, three hundred forty-one".