Base | Representation |
---|---|
bin | 1010010010010101001111… |
… | …0000011101110100010101 |
3 | 1111001020020010011010101101 |
4 | 2210211103300131310111 |
5 | 2440300442322314331 |
6 | 40015433411030101 |
7 | 2245060453451356 |
oct | 244452360356425 |
9 | 44036203133341 |
10 | 11310054104341 |
11 | 3670626764653 |
12 | 1327b6a29b331 |
13 | 6406c2204715 |
14 | 2b15a3ac1d2d |
15 | 149301862061 |
hex | a4953c1dd15 |
11310054104341 has 2 divisors, whose sum is σ = 11310054104342. Its totient is φ = 11310054104340.
The previous prime is 11310054104309. The next prime is 11310054104347. The reversal of 11310054104341 is 14340145001311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9942859432900 + 1367194671441 = 3153230^2 + 1169271^2 .
It is a cyclic number.
It is not a de Polignac number, because 11310054104341 - 25 = 11310054104309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310054104347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655027052170 + 5655027052171.
It is an arithmetic number, because the mean of its divisors is an integer number (5655027052171).
Almost surely, 211310054104341 is an apocalyptic number.
It is an amenable number.
11310054104341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310054104341 is an equidigital number, since it uses as much as digits as its factorization.
11310054104341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 11310054104341 its reverse (14340145001311), we get a palindrome (25650199105652).
The spelling of 11310054104341 in words is "eleven trillion, three hundred ten billion, fifty-four million, one hundred four thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •