113100555042 has 32 divisors (see below), whose sum is σ = 266118955200. Its totient is φ = 35482526784.

The previous prime is 113100555037. The next prime is 113100555049. The reversal of 113100555042 is 240555001311.

113100555042 is a `hidden beast` number, since 1 + 1 + 3 + 100 + 5 + 550 + 4 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 113100554997 and 113100555015.

It is not an unprimeable number, because it can be changed into a prime (113100555049) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61600692 + ... + 61602527.

It is an arithmetic number, because the mean of its divisors is an integer number (8316217350).

Almost surely, 2^113100555042 is an apocalyptic number.

113100555042 is an abundant number, since it is smaller than the sum of its proper divisors (153018400158).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113100555042 is a wasteful number, since it uses less digits than its factorization.

113100555042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123203247 (or 123203241 counting only the distinct ones).

The product of its (nonzero) digits is 3000, while the sum is 27.

Adding to 113100555042 its reverse (240555001311), we get a palindrome (353655556353).

The spelling of 113100555042 in words is "one hundred thirteen billion, one hundred million, five hundred fifty-five thousand, forty-two".