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113101021153 is a prime number
BaseRepresentation
bin110100101010101011…
…0001001111111100001
3101210221012112011200101
41221111112021333201
53323112330134103
6123542523222401
711112514550311
oct1512526117741
9353835464611
10113101021153
1143a6963a20a
1219b05377a01
13a885ac1973
14568cda5441
152e1e493a1d
hex1a55589fe1

113101021153 has 2 divisors, whose sum is σ = 113101021154. Its totient is φ = 113101021152.

The previous prime is 113101021127. The next prime is 113101021157. The reversal of 113101021153 is 351120101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103720711249 + 9380309904 = 322057^2 + 96852^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113101021153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113101021153.

It is not a weakly prime, because it can be changed into another prime (113101021157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550510576 + 56550510577.

It is an arithmetic number, because the mean of its divisors is an integer number (56550510577).

Almost surely, 2113101021153 is an apocalyptic number.

It is an amenable number.

113101021153 is a deficient number, since it is larger than the sum of its proper divisors (1).

113101021153 is an equidigital number, since it uses as much as digits as its factorization.

113101021153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 113101021153 its reverse (351120101311), we get a palindrome (464221122464).

The spelling of 113101021153 in words is "one hundred thirteen billion, one hundred one million, twenty-one thousand, one hundred fifty-three".