Base | Representation |
---|---|
bin | 110100101010101011… |
… | …0001001111111000111 |
3 | 101210221012112011122102 |
4 | 1221111112021333013 |
5 | 3323112330134002 |
6 | 123542523222315 |
7 | 11112514550243 |
oct | 1512526117707 |
9 | 353835464572 |
10 | 113101021127 |
11 | 43a6963a196 |
12 | 19b0537799b |
13 | a885ac1953 |
14 | 568cda5423 |
15 | 2e1e493a02 |
hex | 1a55589fc7 |
113101021127 has 2 divisors, whose sum is σ = 113101021128. Its totient is φ = 113101021126.
The previous prime is 113101021087. The next prime is 113101021153. The reversal of 113101021127 is 721120101311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113101021127 - 210 = 113101020103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113101021099 and 113101021108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113101021157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550510563 + 56550510564.
It is an arithmetic number, because the mean of its divisors is an integer number (56550510564).
Almost surely, 2113101021127 is an apocalyptic number.
113101021127 is a deficient number, since it is larger than the sum of its proper divisors (1).
113101021127 is an equidigital number, since it uses as much as digits as its factorization.
113101021127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 113101021127 its reverse (721120101311), we get a palindrome (834221122438).
The spelling of 113101021127 in words is "one hundred thirteen billion, one hundred one million, twenty-one thousand, one hundred twenty-seven".
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