Base | Representation |
---|---|
bin | 11001101101110101100010… |
… | …110010111000111011001111 |
3 | 112211110100112100001112102111 |
4 | 121231311202302320323033 |
5 | 104311021403004004403 |
6 | 1040313521351004451 |
7 | 32552164664001121 |
oct | 3155654262707317 |
9 | 484410470045374 |
10 | 113101031313103 |
11 | 33045972702849 |
12 | 108278a2669727 |
13 | 4b154c6192822 |
14 | 1dd0194c37211 |
15 | d1203d9aa56d |
hex | 66dd62cb8ecf |
113101031313103 has 2 divisors, whose sum is σ = 113101031313104. Its totient is φ = 113101031313102.
The previous prime is 113101031313073. The next prime is 113101031313107. The reversal of 113101031313103 is 301313130101311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113101031313103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113101031313107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550515656551 + 56550515656552.
It is an arithmetic number, because the mean of its divisors is an integer number (56550515656552).
Almost surely, 2113101031313103 is an apocalyptic number.
113101031313103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113101031313103 is an equidigital number, since it uses as much as digits as its factorization.
113101031313103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 113101031313103 its reverse (301313130101311), we get a palindrome (414414161414414).
The spelling of 113101031313103 in words is "one hundred thirteen trillion, one hundred one billion, thirty-one million, three hundred thirteen thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •