Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …001101110011111110100 |
3 | 11000010100010022012120210 |
4 | 100131111201232133310 |
5 | 122012302343202122 |
6 | 2223325053225420 |
7 | 144466341312564 |
oct | 20352541563764 |
9 | 4003303265523 |
10 | 1131011303412 |
11 | 3a6728439271 |
12 | 163245492270 |
13 | 82866837453 |
14 | 3ca53d62da4 |
15 | 1e64829040c |
hex | 1075586e7f4 |
1131011303412 has 24 divisors (see below), whose sum is σ = 2639069675200. Its totient is φ = 376997582016.
The previous prime is 1131011303371. The next prime is 1131011303419. The reversal of 1131011303412 is 2143031101311.
It is a super-2 number, since 2×11310113034122 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131011303419) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21264 + ... + 1504152.
Almost surely, 21131011303412 is an apocalyptic number.
1131011303412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1131011303412 is an abundant number, since it is smaller than the sum of its proper divisors (1508058371788).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131011303412 is a wasteful number, since it uses less digits than its factorization.
1131011303412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1546455 (or 1546453 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1131011303412 its reverse (2143031101311), we get a palindrome (3274042404723).
The spelling of 1131011303412 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred three thousand, four hundred twelve".
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