1131011332081 has 2 divisors, whose sum is σ = 1131011332082. Its totient is φ = 1131011332080.

The previous prime is 1131011332057. The next prime is 1131011332093. The reversal of 1131011332081 is 1802331101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1114204802481 + 16806529600 = 1055559^2 + 129640^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131011332081 - 2⁵ = 1131011332049 is a prime.

It is a super-2 number, since 2×1131011332081² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1131011372081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565505666040 + 565505666041.

It is an arithmetic number, because the mean of its divisors is an integer number (565505666041).

Almost surely, 2^{1131011332081} is an apocalyptic number.

It is an amenable number.

1131011332081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131011332081 is an equidigital number, since it uses as much as digits as its factorization.

1131011332081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 1131011332081 its reverse (1802331101311), we get a palindrome (2933342433392).

The spelling of 1131011332081 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thirty-two thousand, eighty-one".