11310122023 has 2 divisors, whose sum is σ = 11310122024. Its totient is φ = 11310122022.

The previous prime is 11310122017. The next prime is 11310122059. The reversal of 11310122023 is 32022101311.

It is a weak prime.

It is an emirp because it is prime and its reverse (32022101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310122023 - 2²⁵ = 11276567591 is a prime.

It is a super-3 number, since 3×11310122023³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11310121988 and 11310122006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310122093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655061011 + 5655061012.

It is an arithmetic number, because the mean of its divisors is an integer number (5655061012).

Almost surely, 2^11310122023 is an apocalyptic number.

11310122023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310122023 is an equidigital number, since it uses as much as digits as its factorization.

11310122023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11310122023 its reverse (32022101311), we get a palindrome (43332223334).

The spelling of 11310122023 in words is "eleven billion, three hundred ten million, one hundred twenty-two thousand, twenty-three".