113101230113 has 2 divisors, whose sum is σ = 113101230114. Its totient is φ = 113101230112.

The previous prime is 113101230107. The next prime is 113101230127. The reversal of 113101230113 is 311032101311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108199549969 + 4901680144 = 328937^2 + 70012^2 .

It is a cyclic number.

It is not a de Polignac number, because 113101230113 - 2²² = 113097035809 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113101230091 and 113101230100.

It is not a weakly prime, because it can be changed into another prime (113101230173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550615056 + 56550615057.

It is an arithmetic number, because the mean of its divisors is an integer number (56550615057).

Almost surely, 2^113101230113 is an apocalyptic number.

It is an amenable number.

113101230113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113101230113 is an equidigital number, since it uses as much as digits as its factorization.

113101230113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113101230113 its reverse (311032101311), we get a palindrome (424133331424).

The spelling of 113101230113 in words is "one hundred thirteen billion, one hundred one million, two hundred thirty thousand, one hundred thirteen".