113101230127 has 2 divisors, whose sum is σ = 113101230128. Its totient is φ = 113101230126.

The previous prime is 113101230113. The next prime is 113101230131. The reversal of 113101230127 is 721032101311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113101230127 - 2¹⁵ = 113101197359 is a prime.

It is a super-2 number, since 2×113101230127² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113101230098 and 113101230107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113101230107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550615063 + 56550615064.

It is an arithmetic number, because the mean of its divisors is an integer number (56550615064).

Almost surely, 2^113101230127 is an apocalyptic number.

113101230127 is a deficient number, since it is larger than the sum of its proper divisors (1).

113101230127 is an equidigital number, since it uses as much as digits as its factorization.

113101230127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 113101230127 its reverse (721032101311), we get a palindrome (834133331438).

The spelling of 113101230127 in words is "one hundred thirteen billion, one hundred one million, two hundred thirty thousand, one hundred twenty-seven".