Base | Representation |
---|---|
bin | 1010010010010101011111… |
… | …0111011010001001110011 |
3 | 1111001020101220212002000012 |
4 | 2210211113313122021303 |
5 | 2440301112444030303 |
6 | 40015444312245135 |
7 | 2245062251364221 |
oct | 244452767321163 |
9 | 44036356762005 |
10 | 11310123033203 |
11 | 3670661663955 |
12 | 1327b893a07ab |
13 | 640703589827 |
14 | 2b15acd05b11 |
15 | 14930792a5d8 |
hex | a4957dda273 |
11310123033203 has 2 divisors, whose sum is σ = 11310123033204. Its totient is φ = 11310123033202.
The previous prime is 11310123033163. The next prime is 11310123033343. The reversal of 11310123033203 is 30233032101311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11310123033203 - 228 = 11309854597747 is a prime.
It is a super-4 number, since 4×113101230332034 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (11310123035203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655061516601 + 5655061516602.
It is an arithmetic number, because the mean of its divisors is an integer number (5655061516602).
Almost surely, 211310123033203 is an apocalyptic number.
11310123033203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310123033203 is an equidigital number, since it uses as much as digits as its factorization.
11310123033203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 11310123033203 its reverse (30233032101311), we get a palindrome (41543155134514).
The spelling of 11310123033203 in words is "eleven trillion, three hundred ten billion, one hundred twenty-three million, thirty-three thousand, two hundred three".
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