11310123113 has 2 divisors, whose sum is σ = 11310123114. Its totient is φ = 11310123112.

The previous prime is 11310123107. The next prime is 11310123119. The reversal of 11310123113 is 31132101311.

It is a balanced prime because it is at equal distance from previous prime (11310123107) and next prime (11310123119).

It can be written as a sum of positive squares in only one way, i.e., 9353210944 + 1956912169 = 96712^2 + 44237^2 .

It is an emirp because it is prime and its reverse (31132101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310123113 - 2³⁰ = 10236381289 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11310123091 and 11310123100.

It is not a weakly prime, because it can be changed into another prime (11310123119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655061556 + 5655061557.

It is an arithmetic number, because the mean of its divisors is an integer number (5655061557).

Almost surely, 2^11310123113 is an apocalyptic number.

It is an amenable number.

11310123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310123113 is an equidigital number, since it uses as much as digits as its factorization.

11310123113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11310123113 its reverse (31132101311), we get a palindrome (42442224424).

The spelling of 11310123113 in words is "eleven billion, three hundred ten million, one hundred twenty-three thousand, one hundred thirteen".