Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …110010111100000010001 |
3 | 11000010100012121000100212 |
4 | 100131111212113200101 |
5 | 122012303201114303 |
6 | 2223325135253505 |
7 | 144466354540421 |
oct | 20352546274021 |
9 | 4003305530325 |
10 | 1131012519953 |
11 | 3a672909a278 |
12 | 16324597a295 |
13 | 82866b720b4 |
14 | 3ca5419c481 |
15 | 1e648430ad8 |
hex | 10755997811 |
1131012519953 has 2 divisors, whose sum is σ = 1131012519954. Its totient is φ = 1131012519952.
The previous prime is 1131012519913. The next prime is 1131012520051. The reversal of 1131012519953 is 3599152101311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 868236331264 + 262776188689 = 931792^2 + 512617^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131012519953 - 232 = 1126717552657 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1131012519953.
It is not a weakly prime, because it can be changed into another prime (1131012519913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565506259976 + 565506259977.
It is an arithmetic number, because the mean of its divisors is an integer number (565506259977).
Almost surely, 21131012519953 is an apocalyptic number.
It is an amenable number.
1131012519953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131012519953 is an equidigital number, since it uses as much as digits as its factorization.
1131012519953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36450, while the sum is 41.
The spelling of 1131012519953 in words is "one trillion, one hundred thirty-one billion, twelve million, five hundred nineteen thousand, nine hundred fifty-three".
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