11310131003 has 2 divisors, whose sum is σ = 11310131004. Its totient is φ = 11310131002.

The previous prime is 11310130999. The next prime is 11310131009. The reversal of 11310131003 is 30013101311.

It is a happy number.

11310131003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30013101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310131003 - 2² = 11310130999 is a prime.

It is not a weakly prime, because it can be changed into another prime (11310131009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655065501 + 5655065502.

It is an arithmetic number, because the mean of its divisors is an integer number (5655065502).

Almost surely, 2^11310131003 is an apocalyptic number.

11310131003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310131003 is an equidigital number, since it uses as much as digits as its factorization.

11310131003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 11310131003 its reverse (30013101311), we get a palindrome (41323232314).

The spelling of 11310131003 in words is "eleven billion, three hundred ten million, one hundred thirty-one thousand, three".