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1131020340217 is a prime number
BaseRepresentation
bin10000011101010110000…
…100001100101111111001
311000010100202022022202021
4100131112010030233321
5122012312201341332
62223330015034441
7144466511161135
oct20352604145771
94003322268667
101131020340217
113a67325507a9
1216324850ba21
138286867c781
143ca552363c5
151e648e77c97
hex1075610cbf9

1131020340217 has 2 divisors, whose sum is σ = 1131020340218. Its totient is φ = 1131020340216.

The previous prime is 1131020340209. The next prime is 1131020340227. The reversal of 1131020340217 is 7120430201311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 603579825216 + 527440515001 = 776904^2 + 726251^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131020340217 - 23 = 1131020340209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131020340191 and 1131020340200.

It is not a weakly prime, because it can be changed into another prime (1131020340227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565510170108 + 565510170109.

It is an arithmetic number, because the mean of its divisors is an integer number (565510170109).

Almost surely, 21131020340217 is an apocalyptic number.

It is an amenable number.

1131020340217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131020340217 is an equidigital number, since it uses as much as digits as its factorization.

1131020340217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 1131020340217 its reverse (7120430201311), we get a palindrome (8251450541528).

The spelling of 1131020340217 in words is "one trillion, one hundred thirty-one billion, twenty million, three hundred forty thousand, two hundred seventeen".