Base | Representation |
---|---|
bin | 110100101010101101… |
… | …0010110100000101001 |
3 | 101210221021121001101111 |
4 | 1221111122112200221 |
5 | 3323113120333001 |
6 | 123543002550321 |
7 | 11112530111002 |
oct | 1512532264051 |
9 | 353837531344 |
10 | 113102121001 |
11 | 43a6a220581 |
12 | 19b058083a1 |
13 | a8860b846c |
14 | 568d1b01a9 |
15 | 2e1e60e851 |
hex | 1a55696829 |
113102121001 has 2 divisors, whose sum is σ = 113102121002. Its totient is φ = 113102121000.
The previous prime is 113102120987. The next prime is 113102121007. The reversal of 113102121001 is 100121201311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79919855401 + 33182265600 = 282701^2 + 182160^2 .
It is a cyclic number.
It is not a de Polignac number, because 113102121001 - 29 = 113102120489 is a prime.
It is not a weakly prime, because it can be changed into another prime (113102121007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551060500 + 56551060501.
It is an arithmetic number, because the mean of its divisors is an integer number (56551060501).
Almost surely, 2113102121001 is an apocalyptic number.
It is an amenable number.
113102121001 is a deficient number, since it is larger than the sum of its proper divisors (1).
113102121001 is an equidigital number, since it uses as much as digits as its factorization.
113102121001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 113102121001 its reverse (100121201311), we get a palindrome (213223322312).
The spelling of 113102121001 in words is "one hundred thirteen billion, one hundred two million, one hundred twenty-one thousand, one".
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