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1131021211310 = 25922112265711
BaseRepresentation
bin10000011101010110000…
…111100001011010101110
311000010100210221120122222
4100131112013201122232
5122012312412230220
62223330045435342
7144466521446564
oct20352607413256
94003323846588
101131021211310
113a6732a96211
1216324886bb52
13828688c6103
143ca553c1a34
151e64909ae25
hex107561e16ae

1131021211310 has 16 divisors (see below), whose sum is σ = 2036059129152. Its totient is φ = 452359384800.

The previous prime is 1131021211297. The next prime is 1131021211349. The reversal of 1131021211310 is 131121201311.

It is a super-2 number, since 2×11310212113102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6040646 + ... + 6225065.

It is an arithmetic number, because the mean of its divisors is an integer number (127253695572).

Almost surely, 21131021211310 is an apocalyptic number.

1131021211310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131021211310 is a deficient number, since it is larger than the sum of its proper divisors (905037917842).

1131021211310 is a wasteful number, since it uses less digits than its factorization.

1131021211310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12274939.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1131021211310 its reverse (131121201311), we get a palindrome (1262142412621).

Subtracting from 1131021211310 its reverse (131121201311), we obtain a palindrome (999900009999).

The spelling of 1131021211310 in words is "one trillion, one hundred thirty-one billion, twenty-one million, two hundred eleven thousand, three hundred ten".

Divisors: 1 2 5 10 9221 18442 46105 92210 12265711 24531422 61328555 122657110 113102121131 226204242262 565510605655 1131021211310