Base | Representation |
---|---|
bin | 110100101010101101… |
… | …0101010010100000111 |
3 | 101210221021202011122212 |
4 | 1221111122222110013 |
5 | 3323113130431434 |
6 | 123543004414035 |
7 | 11112530566334 |
oct | 1512532522407 |
9 | 353837664585 |
10 | 113102202119 |
11 | 43a6a276515 |
12 | 19b0584731b |
13 | a88611636a |
14 | 568d1d198b |
15 | 2e1e6288ce |
hex | 1a556aa507 |
113102202119 has 2 divisors, whose sum is σ = 113102202120. Its totient is φ = 113102202118.
The previous prime is 113102202071. The next prime is 113102202137. The reversal of 113102202119 is 911202201311.
It is a strong prime.
It is an emirp because it is prime and its reverse (911202201311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113102202119 is a prime.
It is a super-2 number, since 2×1131022021192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113102202094 and 113102202103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113102202179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551101059 + 56551101060.
It is an arithmetic number, because the mean of its divisors is an integer number (56551101060).
Almost surely, 2113102202119 is an apocalyptic number.
113102202119 is a deficient number, since it is larger than the sum of its proper divisors (1).
113102202119 is an equidigital number, since it uses as much as digits as its factorization.
113102202119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 113102202119 in words is "one hundred thirteen billion, one hundred two million, two hundred two thousand, one hundred nineteen".
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