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11310242031310 = 251131024203131
BaseRepresentation
bin1010010010010101111011…
…1101010110011011001110
31111001020201012202210201111
42210211132331112123032
52440301333430000220
640015504203002234
72245065225013405
oct244453675263316
944036635683644
1011310242031310
1136707128509a2
12132800120937a
13640722122701
142b15c0a4063c
151493130d415a
hexa495ef566ce

11310242031310 has 8 divisors (see below), whose sum is σ = 20358435656376. Its totient is φ = 4524096812520.

The previous prime is 11310242031241. The next prime is 11310242031329. The reversal of 11310242031310 is 1313024201311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×113102420313102 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565512101556 + ... + 565512101575.

It is an arithmetic number, because the mean of its divisors is an integer number (2544804457047).

Almost surely, 211310242031310 is an apocalyptic number.

11310242031310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11310242031310 is a deficient number, since it is larger than the sum of its proper divisors (9048193625066).

11310242031310 is a wasteful number, since it uses less digits than its factorization.

11310242031310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1131024203138.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11310242031310 its reverse (1313024201311), we get a palindrome (12623266232621).

The spelling of 11310242031310 in words is "eleven trillion, three hundred ten billion, two hundred forty-two million, thirty-one thousand, three hundred ten".

Divisors: 1 2 5 10 1131024203131 2262048406262 5655121015655 11310242031310