Base | Representation |
---|---|
bin | 10101000100010010… |
… | …01110110000110111 |
3 | 1002012020020220112122 |
4 | 22202021032300313 |
5 | 141130411411401 |
6 | 5110150110155 |
7 | 550164436502 |
oct | 124211166067 |
9 | 32166226478 |
10 | 11310263351 |
11 | 4884392292 |
12 | 223794b35b |
13 | 10b32a9b2a |
14 | 794196139 |
15 | 462e2921b |
hex | 2a224ec37 |
11310263351 has 2 divisors, whose sum is σ = 11310263352. Its totient is φ = 11310263350.
The previous prime is 11310263299. The next prime is 11310263359. The reversal of 11310263351 is 15336201311.
It is a strong prime.
It is an emirp because it is prime and its reverse (15336201311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11310263351 - 230 = 10236521527 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11310263351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310263359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655131675 + 5655131676.
It is an arithmetic number, because the mean of its divisors is an integer number (5655131676).
Almost surely, 211310263351 is an apocalyptic number.
11310263351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310263351 is an equidigital number, since it uses as much as digits as its factorization.
11310263351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 11310263351 its reverse (15336201311), we get a palindrome (26646464662).
The spelling of 11310263351 in words is "eleven billion, three hundred ten million, two hundred sixty-three thousand, three hundred fifty-one".
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