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11310310019 is a prime number
BaseRepresentation
bin10101000100010010…
…11010001010000011
31002012020100021120002
422202021122022003
5141130414410034
65110151110215
7550165022531
oct124211321203
932166307502
1011310310019
114884414358
12223797236b
1310b32c5148
147941a9151
15462e37e7e
hex2a225a283

11310310019 has 2 divisors, whose sum is σ = 11310310020. Its totient is φ = 11310310018.

The previous prime is 11310309929. The next prime is 11310310021. The reversal of 11310310019 is 91001301311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11310310019 is a prime.

It is a super-2 number, since 2×113103100192 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 11310310021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11310330019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655155009 + 5655155010.

It is an arithmetic number, because the mean of its divisors is an integer number (5655155010).

Almost surely, 211310310019 is an apocalyptic number.

11310310019 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310310019 is an equidigital number, since it uses as much as digits as its factorization.

11310310019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 11310310019 in words is "eleven billion, three hundred ten million, three hundred ten thousand, nineteen".