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113103100963 is a prime number
BaseRepresentation
bin110100101010101111…
…0000101110000100011
3101210221100102211122101
41221111132011300203
53323113343212323
6123543035551231
711112541332016
oct1512536056043
9353840384571
10113103100963
1143a6a82a866
1219b05bbb517
13a88636c518
14568d38737d
152e1e754dad
hex1a55785c23

113103100963 has 2 divisors, whose sum is σ = 113103100964. Its totient is φ = 113103100962.

The previous prime is 113103100961. The next prime is 113103101039. The reversal of 113103100963 is 369001301311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113103100963 - 21 = 113103100961 is a prime.

It is a super-2 number, since 2×1131031009632 (a number of 23 digits) contains 22 as substring.

Together with 113103100961, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (113103100961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551550481 + 56551550482.

It is an arithmetic number, because the mean of its divisors is an integer number (56551550482).

Almost surely, 2113103100963 is an apocalyptic number.

113103100963 is a deficient number, since it is larger than the sum of its proper divisors (1).

113103100963 is an equidigital number, since it uses as much as digits as its factorization.

113103100963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 28.

The spelling of 113103100963 in words is "one hundred thirteen billion, one hundred three million, one hundred thousand, nine hundred sixty-three".