Base | Representation |
---|---|
bin | 10000011101010110101… |
… | …101101111011001000011 |
3 | 11000010101111210120202021 |
4 | 100131112231233121003 |
5 | 122012322443330034 |
6 | 2223331044302311 |
7 | 144500002554625 |
oct | 20352655573103 |
9 | 4003344716667 |
10 | 1131031230019 |
11 | 3a6738709439 |
12 | 1632500a1997 |
13 | 8286a9c3342 |
14 | 3ca5686cc15 |
15 | 1e649dc96b4 |
hex | 10756b6f643 |
1131031230019 has 2 divisors, whose sum is σ = 1131031230020. Its totient is φ = 1131031230018.
The previous prime is 1131031229983. The next prime is 1131031230029. The reversal of 1131031230019 is 9100321301311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131031230019 - 219 = 1131030705731 is a prime.
It is a super-2 number, since 2×11310312300192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131031229975 and 1131031230002.
It is not a weakly prime, because it can be changed into another prime (1131031230029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565515615009 + 565515615010.
It is an arithmetic number, because the mean of its divisors is an integer number (565515615010).
Almost surely, 21131031230019 is an apocalyptic number.
1131031230019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131031230019 is an equidigital number, since it uses as much as digits as its factorization.
1131031230019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 1131031230019 in words is "one trillion, one hundred thirty-one billion, thirty-one million, two hundred thirty thousand, nineteen".
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