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11310414169 is a prime number
BaseRepresentation
bin10101000100010011…
…10011100101011001
31002012020112120102111
422202021303211121
5141130431223134
65110153232321
7550165635265
oct124211634531
932166476374
1011310414169
11488448562a
122237a026a1
1310b3330682
147941d50a5
15462e58c64
hex2a2273959

11310414169 has 2 divisors, whose sum is σ = 11310414170. Its totient is φ = 11310414168.

The previous prime is 11310414131. The next prime is 11310414179. The reversal of 11310414169 is 96141401311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6373946569 + 4936467600 = 79837^2 + 70260^2 .

It is an emirp because it is prime and its reverse (96141401311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310414169 - 227 = 11176196441 is a prime.

It is a super-2 number, since 2×113104141692 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11310414169.

It is not a weakly prime, because it can be changed into another prime (11310414179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655207084 + 5655207085.

It is an arithmetic number, because the mean of its divisors is an integer number (5655207085).

Almost surely, 211310414169 is an apocalyptic number.

It is an amenable number.

11310414169 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310414169 is an equidigital number, since it uses as much as digits as its factorization.

11310414169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 11310414169 in words is "eleven billion, three hundred ten million, four hundred fourteen thousand, one hundred sixty-nine".