Base | Representation |
---|---|
bin | 10101000100010011… |
… | …10011100100110011 |
3 | 1002012020112120101002 |
4 | 22202021303210303 |
5 | 141130431223011 |
6 | 5110153232215 |
7 | 550165635212 |
oct | 124211634463 |
9 | 32166476332 |
10 | 11310414131 |
11 | 48844855a5 |
12 | 2237a0266b |
13 | 10b3330653 |
14 | 7941d5079 |
15 | 462e58c3b |
hex | 2a2273933 |
11310414131 has 2 divisors, whose sum is σ = 11310414132. Its totient is φ = 11310414130.
The previous prime is 11310414127. The next prime is 11310414169. The reversal of 11310414131 is 13141401311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11310414131 - 22 = 11310414127 is a prime.
It is a super-2 number, since 2×113104141312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11310414191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655207065 + 5655207066.
It is an arithmetic number, because the mean of its divisors is an integer number (5655207066).
Almost surely, 211310414131 is an apocalyptic number.
11310414131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310414131 is an equidigital number, since it uses as much as digits as its factorization.
11310414131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 11310414131 its reverse (13141401311), we get a palindrome (24451815442).
The spelling of 11310414131 in words is "eleven billion, three hundred ten million, four hundred fourteen thousand, one hundred thirty-one".
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