11310434131 has 2 divisors, whose sum is σ = 11310434132. Its totient is φ = 11310434130.

The previous prime is 11310434099. The next prime is 11310434173. The reversal of 11310434131 is 13143401311.

It is a weak prime.

It is an emirp because it is prime and its reverse (13143401311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310434131 - 2⁵ = 11310434099 is a prime.

It is a super-2 number, since 2×11310434131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11310434231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655217065 + 5655217066.

It is an arithmetic number, because the mean of its divisors is an integer number (5655217066).

Almost surely, 2^11310434131 is an apocalyptic number.

11310434131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310434131 is an equidigital number, since it uses as much as digits as its factorization.

11310434131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11310434131 its reverse (13143401311), we get a palindrome (24453835442).

The spelling of 11310434131 in words is "eleven billion, three hundred ten million, four hundred thirty-four thousand, one hundred thirty-one".