11310434132 has 12 divisors (see below), whose sum is σ = 19798392180. Its totient is φ = 5653750656.

The previous prime is 11310434131. The next prime is 11310434173. The reversal of 11310434132 is 23143401311.

It can be written as a sum of positive squares in 2 ways, for example, as 1351591696 + 9958842436 = 36764^2 + 99794^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11310434098 and 11310434107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11310434131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 349157 + ... + 380172.

It is an arithmetic number, because the mean of its divisors is an integer number (1649866015).

Almost surely, 2^11310434132 is an apocalyptic number.

It is an amenable number.

11310434132 is a deficient number, since it is larger than the sum of its proper divisors (8487958048).

11310434132 is a wasteful number, since it uses less digits than its factorization.

11310434132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 733210 (or 733208 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11310434132 its reverse (23143401311), we get a palindrome (34453835443).

The spelling of 11310434132 in words is "eleven billion, three hundred ten million, four hundred thirty-four thousand, one hundred thirty-two".