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113105425087 is a prime number
BaseRepresentation
bin110100101010110011…
…0111101001010111111
3101210221111210220202001
41221111212331022333
53323114442100322
6123543201443131
711112600151624
oct1512546751277
9353844726661
10113105425087
1143a71077a26
1219b069404a7
13a8869a4345
14568d7d034b
152e1ea63827
hex1a559bd2bf

113105425087 has 2 divisors, whose sum is σ = 113105425088. Its totient is φ = 113105425086.

The previous prime is 113105425067. The next prime is 113105425099. The reversal of 113105425087 is 780524501311.

It is a strong prime.

It is an emirp because it is prime and its reverse (780524501311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113105425087 is a prime.

It is a super-3 number, since 3×1131054250873 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113105425067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56552712543 + 56552712544.

It is an arithmetic number, because the mean of its divisors is an integer number (56552712544).

Almost surely, 2113105425087 is an apocalyptic number.

113105425087 is a deficient number, since it is larger than the sum of its proper divisors (1).

113105425087 is an equidigital number, since it uses as much as digits as its factorization.

113105425087 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 37.

Adding to 113105425087 its reverse (780524501311), we get a palindrome (893629926398).

The spelling of 113105425087 in words is "one hundred thirteen billion, one hundred five million, four hundred twenty-five thousand, eighty-seven".