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1131054404552 = 23141381800569
BaseRepresentation
bin10000011101011000000…
…110001001001111001000
311000010110010101222020022
4100131120012021033020
5122012344411421202
62223333233120012
7144500403545102
oct20353006111710
94003403358208
101131054404552
113a674a7a7846
121632579b9008
1382872748697
143ca59982572
151e64be55ea2
hex107581893c8

1131054404552 has 8 divisors (see below), whose sum is σ = 2120727008550. Its totient is φ = 565527202272.

The previous prime is 1131054404537. The next prime is 1131054404563. The reversal of 1131054404552 is 2554044501311.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 1130594130436 + 460274116 = 1063294^2 + 21454^2 .

It is a tau number, because it is divible by the number of its divisors (8).

It is a super-3 number, since 3×11310544045523 (a number of 37 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70690900277 + ... + 70690900292.

Almost surely, 21131054404552 is an apocalyptic number.

It is an amenable number.

1131054404552 is a deficient number, since it is larger than the sum of its proper divisors (989672603998).

1131054404552 is a wasteful number, since it uses less digits than its factorization.

1131054404552 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141381800575 (or 141381800571 counting only the distinct ones).

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 1131054404552 its reverse (2554044501311), we get a palindrome (3685098905863).

The spelling of 1131054404552 in words is "one trillion, one hundred thirty-one billion, fifty-four million, four hundred four thousand, five hundred fifty-two".

Divisors: 1 2 4 8 141381800569 282763601138 565527202276 1131054404552