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113110030133 is a prime number
BaseRepresentation
bin110100101010111100…
…0100001011100110101
3101210221211110212200022
41221111320201130311
53323122131431013
6123543444254525
711112654251462
oct1512570413465
9353854425608
10113110030133
1143a73732851
1219b083a1445
13a887927419
14569026c669
152e20173008
hex1a55e21735

113110030133 has 2 divisors, whose sum is σ = 113110030134. Its totient is φ = 113110030132.

The previous prime is 113110030087. The next prime is 113110030147. The reversal of 113110030133 is 331030011311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61452922609 + 51657107524 = 247897^2 + 227282^2 .

It is a cyclic number.

It is not a de Polignac number, because 113110030133 - 26 = 113110030069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113110030933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555015066 + 56555015067.

It is an arithmetic number, because the mean of its divisors is an integer number (56555015067).

Almost surely, 2113110030133 is an apocalyptic number.

It is an amenable number.

113110030133 is a deficient number, since it is larger than the sum of its proper divisors (1).

113110030133 is an equidigital number, since it uses as much as digits as its factorization.

113110030133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 113110030133 its reverse (331030011311), we get a palindrome (444140041444).

The spelling of 113110030133 in words is "one hundred thirteen billion, one hundred ten million, thirty thousand, one hundred thirty-three".