Base | Representation |
---|---|
bin | 1010010010011000110010… |
… | …1111110001010111110111 |
3 | 1111001022200202021000110001 |
4 | 2210212030233301113313 |
5 | 2440304422104123412 |
6 | 40020112324012131 |
7 | 2245123243362163 |
oct | 244461457612767 |
9 | 44038622230401 |
10 | 11311010223607 |
11 | 3670a77437166 |
12 | 1328196531047 |
13 | 640815319873 |
14 | 2b1654a89ca3 |
15 | 14935a776957 |
hex | a498cbf15f7 |
11311010223607 has 2 divisors, whose sum is σ = 11311010223608. Its totient is φ = 11311010223606.
The previous prime is 11311010223599. The next prime is 11311010223631. The reversal of 11311010223607 is 70632201011311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311010223607 - 23 = 11311010223599 is a prime.
It is a super-2 number, since 2×113110102236072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311010223307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655505111803 + 5655505111804.
It is an arithmetic number, because the mean of its divisors is an integer number (5655505111804).
Almost surely, 211311010223607 is an apocalyptic number.
11311010223607 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311010223607 is an equidigital number, since it uses as much as digits as its factorization.
11311010223607 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 11311010223607 its reverse (70632201011311), we get a palindrome (81943211234918).
The spelling of 11311010223607 in words is "eleven trillion, three hundred eleven billion, ten million, two hundred twenty-three thousand, six hundred seven".
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