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1131103002041 is a prime number
BaseRepresentation
bin10000011101011010111…
…111100001110110111001
311000010120111211222110022
4100131122333201312321
5122012444332031131
62223342130500225
7144501533611535
oct20353277416671
94003514758408
101131103002041
113a677517a861
12163270134675
138287c8325ac
143ca621d2bc5
151e65135537b
hex1075afe1db9

1131103002041 has 2 divisors, whose sum is σ = 1131103002042. Its totient is φ = 1131103002040.

The previous prime is 1131103002013. The next prime is 1131103002047. The reversal of 1131103002041 is 1402003011311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1118879488441 + 12223513600 = 1057771^2 + 110560^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131103002041 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131103002047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565551501020 + 565551501021.

It is an arithmetic number, because the mean of its divisors is an integer number (565551501021).

Almost surely, 21131103002041 is an apocalyptic number.

It is an amenable number.

1131103002041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131103002041 is an equidigital number, since it uses as much as digits as its factorization.

1131103002041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1131103002041 its reverse (1402003011311), we get a palindrome (2533106013352).

The spelling of 1131103002041 in words is "one trillion, one hundred thirty-one billion, one hundred three million, two thousand, forty-one".