1131103002013 has 2 divisors, whose sum is σ = 1131103002014. Its totient is φ = 1131103002012.

The previous prime is 1131103001999. The next prime is 1131103002041. The reversal of 1131103002013 is 3102003011311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 899836268409 + 231266733604 = 948597^2 + 480902^2 .

It is an emirp because it is prime and its reverse (3102003011311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131103002013 - 2⁵ = 1131103001981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131103002083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565551501006 + 565551501007.

It is an arithmetic number, because the mean of its divisors is an integer number (565551501007).

Almost surely, 2^{1131103002013} is an apocalyptic number.

It is an amenable number.

1131103002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131103002013 is an equidigital number, since it uses as much as digits as its factorization.

1131103002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1131103002013 its reverse (3102003011311), we get a palindrome (4233106013324).

The spelling of 1131103002013 in words is "one trillion, one hundred thirty-one billion, one hundred three million, two thousand, thirteen".