113111141404421 has 2 divisors, whose sum is σ = 113111141404422. Its totient is φ = 113111141404420.

The previous prime is 113111141404337. The next prime is 113111141404447. The reversal of 113111141404421 is 124404141111311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97317948780196 + 15793192624225 = 9864986^2 + 3974065^2 .

It is an emirp because it is prime and its reverse (124404141111311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113111141404421 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113111141400421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555570702210 + 56555570702211.

It is an arithmetic number, because the mean of its divisors is an integer number (56555570702211).

Almost surely, 2^{113111141404421} is an apocalyptic number.

It is an amenable number.

113111141404421 is a deficient number, since it is larger than the sum of its proper divisors (1).

113111141404421 is an equidigital number, since it uses as much as digits as its factorization.

113111141404421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 29.

Adding to 113111141404421 its reverse (124404141111311), we get a palindrome (237515282515732).

The spelling of 113111141404421 in words is "one hundred thirteen trillion, one hundred eleven billion, one hundred forty-one million, four hundred four thousand, four hundred twenty-one".