Base | Representation |
---|---|
bin | 10101000100011001… |
… | …00010100110001111 |
3 | 1002012021212222202122 |
4 | 22202030202212033 |
5 | 141131122143043 |
6 | 5110220443155 |
7 | 550205012243 |
oct | 124214424617 |
9 | 32167788678 |
10 | 11311131023 |
11 | 4884925175 |
12 | 22380a94bb |
13 | 10b3521a4a |
14 | 794340423 |
15 | 46304b368 |
hex | 2a232298f |
11311131023 has 2 divisors, whose sum is σ = 11311131024. Its totient is φ = 11311131022.
The previous prime is 11311131011. The next prime is 11311131043. The reversal of 11311131023 is 32013111311.
It is a weak prime.
It is an emirp because it is prime and its reverse (32013111311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11311131023 - 232 = 7016163727 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11311130992 and 11311131010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311131043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655565511 + 5655565512.
It is an arithmetic number, because the mean of its divisors is an integer number (5655565512).
Almost surely, 211311131023 is an apocalyptic number.
11311131023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311131023 is an equidigital number, since it uses as much as digits as its factorization.
11311131023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11311131023 its reverse (32013111311), we get a palindrome (43324242334).
The spelling of 11311131023 in words is "eleven billion, three hundred eleven million, one hundred thirty-one thousand, twenty-three".
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