Base | Representation |
---|---|
bin | 10101000100011001… |
… | …00101000101100111 |
3 | 1002012021220111202102 |
4 | 22202030211011213 |
5 | 141131123004343 |
6 | 5110221002315 |
7 | 550205054054 |
oct | 124214450547 |
9 | 32167814672 |
10 | 11311141223 |
11 | 48849318a8 |
12 | 22380b339b |
13 | 10b3526595 |
14 | 79434402b |
15 | 46304e3b8 |
hex | 2a2325167 |
11311141223 has 2 divisors, whose sum is σ = 11311141224. Its totient is φ = 11311141222.
The previous prime is 11311141189. The next prime is 11311141253. The reversal of 11311141223 is 32214111311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311141223 - 222 = 11306946919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11311141195 and 11311141204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311141253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655570611 + 5655570612.
It is an arithmetic number, because the mean of its divisors is an integer number (5655570612).
Almost surely, 211311141223 is an apocalyptic number.
11311141223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311141223 is an equidigital number, since it uses as much as digits as its factorization.
11311141223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 20.
Adding to 11311141223 its reverse (32214111311), we get a palindrome (43525252534).
The spelling of 11311141223 in words is "eleven billion, three hundred eleven million, one hundred forty-one thousand, two hundred twenty-three".
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