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11311200000000 = 21132581571
BaseRepresentation
bin1010010010011001100000…
…0011101101100000000000
31111001100011222100122201100
42210212120003231200000
52440310314200000000
640020143223334400
72245131036426135
oct244463003554000
944040158318640
1011311200000000
113671064576a5a
121328229bb1400
136408457345a4
142b1671d6a58c
1514936c261a00
hexa49980ed800

11311200000000 has 648 divisors, whose sum is σ = 40862000563020. Its totient is φ = 3014400000000.

The previous prime is 11311199999971. The next prime is 11311200000157. The reversal of 11311200000000 is 211311.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 7199999215 + ... + 7200000785.

Almost surely, 211311200000000 is an apocalyptic number.

11311200000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11311200000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20431000281510).

11311200000000 is an abundant number, since it is smaller than the sum of its proper divisors (29550800563020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11311200000000 is an frugal number, since it uses more digits than its factorization.

11311200000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1639 (or 1581 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 9.

Adding to 11311200000000 its reverse (211311), we get a palindrome (11311200211311).

The spelling of 11311200000000 in words is "eleven trillion, three hundred eleven billion, two hundred million", and thus it is an aban number.